15p^2+80p=80=0

Solution for 15p^2+80p=80=0 equation:

15p^2+80p=80=0

We move all terms to the left:

15p^2+80p-(80)=0

a = 15; b = 80; c = -80;
Δ = b2-4ac
Δ = 802-4·15·(-80)
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-40\sqrt{7}}{2*15}=\frac{-80-40\sqrt{7}}{30}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+40\sqrt{7}}{2*15}=\frac{-80+40\sqrt{7}}{30}
$